can you answer this?

sure,

the acid protinates the -OH attached and forms water. This leaves an unhappy carbon, the carbon then decides to share electrons with its neighboring carbon. The other carbon finds this favorable and releases its hydrogen.

if we take the example: CH3CH2OH + H2SO4-------> CH2=CH2 + H2O + H2SO4

sulfuric acid acts as a catalyst. The reaction takes place in acid medium, provided by the sulfuric acid. Symbolic, the acid medium is represented by protons H+. The proton H+ attacks the OH group. In this way we preform water as a cation: H2O+. Then this cation is eliminated, and we obtain a carbocation. This carbocation eliminates H+ and forms the alkene.

The mechanism:

CH3CH2OH + H+ -----> CH3CH2OH2+ --------> CH3CH2+ + H2O--------> CH2=CH2 + H+

This reaction is an elimination. It can be a monomolecular elimination, or a bimolecular elimination, depending on the reactants.

Alkenes can be synthesized from alcohols via dehydration that eliminates water. For example, the dehydration of ethanol produces ethene:

CH3CH2OH + H2SO4 (conc. aq) → CH3CH2OSO3H + H2O → H2C=CH2 + H2SO4 + H2O

Other alcohol eliminations are the Chugaev elimination and the Grieco elimination in which the alcohol group is converted to a short-lived intermediate first.