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differentiate wth respect to x....?
tan^-1(6x/1-2x^2) , (cos x)^2x Please indicate you leve of education at the end of your answer and a star if you get the right answer
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- 1 decade agoFavourite answer
assuming that the comma means different questions,
y= tan^-1(6x/1-2x^2)
y'= (6-4x)/(4*((x-3)^2) *(x^2)+1)
y= (cos x)^2x
y'= 2cos(x)^(2x) * (log(cos(x))-xtan(x))
college (soon to be) sophomore
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