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How do I factor this quartic equation? ?
6x^4-11x^3-51x^2+98x-27=0
What are the factors for this quartic?
I can't seem to figure it out...
oh and please tell me how too if you can. thanks!
it's from solve and graph the equations:
y=x and y=6x^4-11X^2-51x^2+99x=27
do you think it's possible that it would just simply be no solution? I know for a fact that the problem is correct. i have looked it over more then 3 times.
3 Answers
- Roger the MoleLv 71 decade agoFavourite answer
Supposing that you haven't yet copied the problem correctly, and that you mean:
6x^4 -11x^3 -51x^2 +99x -27=0
looking at the last term, -27, it's a good guess that some factor ends in 3, so trying x-3 we get:
(x-3) (6x^3 +7x^2 -30x + 9)
x-3 doesn't work again, so trying x+3:
(x-3)(x+3) (6^x2 - 11x +3)
and factoring the last quadratic by inspection:
(x-3)(x+3)(2x - 3)(3x - 1)
- Anonymous6 years ago
Hope this helps!
Source(s): factor quartic equation: https://bitly.im/c16/how-do-i-factor-this-quartic-...
