Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
How do I solve this, please?
Show that
2x^2 - 3x - 20 = 0
Merci, i know i was being a bit stupid but because it was 2x I kept putting (2x+5)(x-2) for some crazy reason.
8 Answers
- 1 decade ago
This is how we solve Quadratic Equation:
2x^2-3x-20=0
2x^2-8x+5x-20=0
2x(x-4)+5(x-4)=0
(2x+5)(x-4)=0
x=-5/2,4
- Anonymous1 decade ago
(2x+5)(x-4)=0 so x=-5/2 or x=4
- 1 decade ago
2x squared -3x -20=0 +20
2x squared -3x = 20 i then used elimination
x=1
2-3=-1
x=2
8-6= 2
x=3
18-9=9
x=4
32-12=20
so thats your answer
x=4
- >_<Lv 41 decade ago
2x^2-3x-20=0
(2x+5)(x-4)
2x+5=0
-5+5=0
2x=-5
x=-2.5 or -5/2
Now for the x-4=0
4-4=0
x=4
So the answers are x=-2.5 or -5/2
and x=4
Source(s): I just studied this in AP Algebra 2!!! - Anonymous1 decade ago
enter it into a graphing calculator in one of the y= spots
in the other enter in y=0
then intersect the two points
orr you could do the quadratic equation..
b plus or minus the square root of (b squared minus 4(a)(c)) all divided by 2a.
so 2= a, b= -3 and c=-20
-3 plus or minus the square root of (-3squared minus 4*2*-20) all divided by 2*2
- 1 decade ago
I know its mean, but I would help you if you actually showed you had tried the question and had some sort of idea of an answer :o)