Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
How far would an object travel with an initial velocity of 30 m/s and a cofficient of kinetic friction of .2?
2 Answers
- ?Lv 68 years agoFavourite answer
when the kinetic energy is dissipated by friction
0.5 m V^2 = (Mu) m g d
where m = mass
V= velocitiy
Mu = coefficient of friction
g = acceleration of gravity
d = distance
Solve for d
- Mark PLv 78 years ago
If the friction force is the ONLY force slowing down an object, the object's deceleration is given by
a = -(mu)g. Here a = -(0.2)(9.8) = -1.96 m/s^2
Vf^2 = Vi^2 + 2*a*d => 0 = (30)^2 + 2(-1.96)(d) => d = about 230 m
