Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Can someone please explain these algebra1 problems please!?
http://i44.tinypic.com/2nvs4sp.jpg
Can someone explain these using numbers and graphs if possible? Thanks
2 Answers
- Wile E.Lv 78 years agoFavourite answer
12.) y = - 5x + 3
Slope = - 5
The slope of a parallel line will have the same slope as the original line, so
m = - 5
x = 2
y = 0
b = y - mx:
b = 0 - [- 5(2)]
b = - (- 10)
b = 10
Equation of Line:
y = - 5x + 10
¯¯¯¯¯¯¯¯¯¯¯¯
13.) y = - x - 4
m = - 1
x = - 1
y = 4
b = 4 - [- 1(- 1)]
b = 4 - 1
b = 3
Equation of Line:
y = - x + 3
¯¯¯¯¯¯¯¯¯
14.) y = ¼ x + 2
m = ¼
x = 4
y = - 9
b = - 9 - ¼ (4)
b = - 9 - 1
b = - 10
Equation of Line:
y = ¼ x - 10
¯¯¯¯¯¯¯¯¯¯¯
Source(s): 7/7/13 - Fazaldin ALv 78 years ago
Given line : y = -5x + 3 ............................................ [1]
a.)
A line parallel to [1] and passin to point(2, 0) is : y = -5(x-2),
OR,
y = -5x + 10 >=======================================< ANSWER
b.)
A line Perpendicular to [1] and having point(2, 0) is : y = (1/5)(x-2),
OR,
y = x/5 - 2/5 = 0.2x - 0.4 >================================< ANSWER
Similarly Solve the Left-overs ..........................