Can someone please explain these algebra 1 problems!?

If it says, parallel then use the same slope. Number 3: (-1,3), y=2x+2

1 way of finding the equation is using the slope intercept from, y=mx+b.

If it's parallel, just use the same slope which is m=2.

(If it's perpendicular, use the negative reciprocal which is -(1/m)= -(1/2)

After identifying the slope, identify the other parts of the equation.

You have P(-1,3). The x-coordinate is 1 and the y coordinate is -3.

Plug your x, y and m values in the slope intercept form and solve for b. 3=2(-1)+b

b= 3+2 = 5

So an equation parallel to y=2x+2 which passes through (-1,3) is y=2x+5

Basically it's:

1. Identify your slope (same slope if parallel and negative reciprocal if perpendicular.)

2. Identify your x and y coordinates [ (x,y) ]

3. Plug them in the slope intercept form, y=mx+b, to solve for b.

4. Then use your slope value and the b value that you got.

Good luck and I hope I helped. Feel free to hit me up if you need some Algebra 1 help.

y = 2x + b ....................[since parallel lines have same slope]

3 = 2(-1) + b ................... [sub x and y values from the given point]

3 = -2 + b

b = 5

y = 2x + 5