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? asked in Science & MathematicsMathematics · 3 years ago

Maths help ples?

y = 16 x 10^8k

Find an expression, in terms of k, for y^5/4

Give your answer in standard form

3 Answers

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  • Como
    Lv 7
    3 years ago

    Will assume that you mean

    y = 16 x 10^(8k)

    y^(5/4) = [ 16 x 10^(8k) ]^(5/4)

    y^(5/4) = 32 x 10^(10k)

    y^(5/40 = 3•2 x 10^(10k + 1)

  • ?
    Lv 7
    3 years ago

    y^(5/4) = (16 * 10^8k)^(5/4)

    y^(5/4) = 16^(5/4) * (10^(8k))^(5/4)

    y^(5/4) = (2^4)^(5/4) * 10^(8k * 5/4)

    y^(5/4) = 2^5 * 10^(10k)

    y^(5/4) = 32 * 10^(10k)

    y^(5/4) = 3.2 * 10^(10k+1)

  • billrussell42
    Lv 7
    3 years ago

    y^5/4 = (6 x 10^8k)^5/4

    = 6^(5/4) x (10^8k)^5/4

    = 6^(5/4) x 10^(8k•5/4)

    = 6^(5/4) x 10^(10k)

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