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? asked in Science & MathematicsMathematics · 2 years ago

Maths Help?

Assume that the surface area of a cell in the lungs that is exposed to air is square-shaped. As a result of a prescription drug if the cell swells and its length doubles, by what factor would its exposed surface area increase?

Also,

If the cell in the above question was cube-shaped, by what factor would its volume increase when its length increases by a factor of two?

2 Answers

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  • Steve A
    Lv 7
    2 years ago

    Square-shaped? Does this mean a cube (6 squares)? Surely, it is not 2D.

    SA = 2Lw +2Lh + 2wh

    L = w = h

    SA = 6w^2 originally

    SA = 2(2w)w +2(2w)h + 2wh = 10w^2

    SA increased 2/3 times. The new shape has 5/3 times the surface area of the original.

    V = Lwh = w^3

    New V = 2w*wh = 2w^3

  • 胡雪8°
    Lv 7
    2 years ago

    Factor of area increase

    = 2²

    = 4

    Factor of volume increase

    = 2³

    = 8

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