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2 Answers
- PinkgreenLv 71 month ago
sqr[(r(r^2-3))^2-4]/(r^2-1)
=
sqr[(r^4-6r^2+9)r^2-4]/(r^2-1)
=
sqr[r^6-6r^4+9r^2-4]/(r^2-1)
=
sqr[(r^2-1)(r^4-5r^2+4)]/(r^2-1)
=
sqr[(r^2-1)(r^2-4)(r^2-1)]/(r^2-1)
=
sqr[(r^2-4)(r^2-1)^2]/(r^2-1)
=
(r^2-1)sqr(r^2-4)/r^2-1)
=
sqr(r^2-4)
This proves that my previous result in another problem
x+y+z=
(3/2){r+/-sqr[(r(r^2-3))^2-4]/(r^2-1)} is exactly=
(3/2)[r+/-sqr(r^2-4)]
That is what I actually want.
Stars are awarded to those who
successfully solves the problem.
- ?Lv 71 month ago
What is strange is that you're a level 7 here and you even solve much much harder problems like differential equations and calculus. Yet you're asking to solve a very easy algebra question?
Anw, hint: Square both sides. ]
So, is it true?
Or, can you find a counterexample?
