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4 Answers
- Engr. RonaldLv 71 week ago
Given
a₁ = 36
r = -2/3
............a₁
S = -----------
.........1 - r
............ 36
S = -------------
........1 -(-2/3)
S = 108/5 Answer//
Answer is B. 108/5
- ?Lv 71 week ago
36 - 24 + 16 - 32/3 + ...
Infinite sum:
sum_(n=1)^∞ (-2)^(1 + n) 3^(3 - n) = 108/5 = 21.6
Answer choice:
B. 108/5
- Ian HLv 71 week ago
Each step is -2/3 of the previous one, (so, a geometric series)
Use infinite sum formula S = a/(1 – r) = 36/(1 + 2/3) = 21.6, (which was B)
- PopeLv 71 week ago
That is a geometric series with initial term 36 and common ratio -2/3.
36/[1 - (-2/3)] = 36/(5/3) = 108/5