Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

? asked in Science & MathematicsChemistry · 6 days ago

How would I Find the energy in joules that would that would be required to raise the temperature of 20 g of ice at -20°C to steam at 120°C? ?

Attachment image

1 Answer

Relevance
  • 6 days ago
    Favourite answer

    You will do 5 separate calculations and then add the results of those together.

    1) heat to raise temp of ice from -20°C to 0°C:

    q = m c (T2-T1)

    q = 20 g (2.06 J/g°C) (0 - -20°C) = 824 J

    2) heat to melt ice at 0°C:

    q = 20 g (334.72 J/g) = 6694 J

    3) heat to raise temp of water from 0°C to 100°C:

    q = m c (T2-T1)

    q = 20 g (4.184 J/g°C) (100 - 0°C) = 8368 J

    4) heat to vaporize water:

    q = 20 g (2259.36 J/g) = 45187 J

    5) heat to raise temp of steam from 100°C to 120°C:

    q = m c (T2-T1)

    q = 20 g (2.02 J/g°C) (120-100) = 808 J

    Total heat = 61836 J

Still have questions? Get answers by asking now.