Linear Momentum Question?

Question

A space probe on its way to the Moon consists of a 900 kg Lander and an 1000 kg Orbiter. The Orbiter and the Lander arrive at the Moon as one unit and then are separated by means of explosive bolts. An impulse of 2000 N·s is imparted to the Lander and Orbiter by the detonation of the explosive bolts. What are the relative velocities of the Lander and Orbiter with respect to each other after detonation of the explosive bolts?

Anonymous · Accepted Answer

First off some important equations, impulse=momentum, f delta t = m delta v. 
since we know f, t and m, we can also find v.

Assuming the lander is on the surface and completely rigid, we can assume the full impulse force goes into the orbiter.  And assuming there is no residual clinging (not scientific term, but you know what I mean) between the orbiter and lander at separation, the 2000Ns impulse leave you to pick the mass you calculate very carefully.  I pick the orbiter.  So, 2000= m times v, and since we now know m = 1000, v is obviously 2m/s  

At least, this is directly after detonation, of course afterwards the moon's gravity will affect the speed and all that, but I think your problem is simplified enough to be answered here.

? · Answer

Angular momentum is likewise a scalar. in spite of the shown fact that: angles themselves are actually not vectors. you may coach that angles a, b and c, in the event that they're orthogonal to a minimum of one yet another, provide distinctive reulting angles for a+b+c vs. a+c+b, case in point.

Linear Momentum Question?

2 Answers