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Zac
Zac asked in Science & MathematicsChemistry · 1 decade ago

Help with titration calculations!?

So...I did a titration with KMnO4 and FeSO4(NH4)2SO4*6H2O and found a concentration for KMnO4(aq) which is .0371 mol/L.

I had to do another titration where I titrated KMnO4(aq) with 10.0 mL of H2O2(l) and 5 mL of H2SO4(aq). I titrated until a pink color change, which was, on average, at 11.96 mL added.

How do I find the concentration of H2O2?

1 Answer

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  • Dr.A
    Lv 7
    1 decade ago
    Favourite answer

    2 MnO4- + 5 H2O2 + 6 H+ = 2 Mn2+ + 5 O2 + 8 H2O

    moles MnO4- = 0.01196 L x 0.0371 =0.0004437

    moles H2O2 = 0.0004437 x 5/2=0.00111

    [H2O2]= 0.00111/ 0.0100 L=0.111 M

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