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Simple trig intercept problem.?
Solve 4sin(3tpi)=0 for t if 0 < t < .6666666667
Thanks all!
2 Answers
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- 10 years agoFavourite answer
We know : .6666666667 = 2/3
4sin( 3tπ ) = 0
<=> sin( 3tπ ) = 0
<=> 3tπ = kπ ( k ∈ ℤ )
<=> 3t = k
We have :
0 < t < 2/3
<=> 0 < 3t < 2
<=> 0 < k < 2 ( We have k = 3t )
=> k = 1
Answer : k = 1
Source(s): I'm a Vietnamese student
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