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2A+3B→CΔHrxn=−173kJ Determine the amount of heat emitted. 1. 2mol a 2. 8 mol a 3. 4 mol b 4. 8 mol b?
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- jacob sLv 71 month ago
2A+3B→C ΔHrxn=−173kJ
2 mole of A gives -173Kj
1.2 moles of A gives = -173*1.2/2 = -103Kj
2.8. moles of A gives = -173 * 2.8/2 = -242.2 kJ
3 mole of B gives -173Kj
3.4 moles of B gives = -173*3.4/3 = -196 Kj
3 mole of B gives -173Kj
4.8 moles of B gives = -173*4.8/3 = -276.8 KJ
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