Yahoo Answers is shutting down on 4 May 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
A Chemistry Question?
what mass of ammonia can be formed when 100g of hydrogen reacts with 60L of nitrogen at SATP?
2 Answers
- 1 decade agoFavourite answer
Haber process. N2 + 3H2 ---> 2NH3
100 g H2 (1 mol H2 / 2 g H2) = 50 mol H2
50 mol H2 (2 mol NH3 / 3 mol H2) = 33 mol NH3
60 L N2 (1.25 g / L N2) ( 1 mol N2 / 28 g N2 ) = 2.68 mol N2
2.68 mol N2 (2 mol NH3 / 1 mol N2) = 5.4 mol (N2 limiting , only produces 5.4 mol ammonia)
5.4 mol NH3 (17 g NH3 / mol NH3 ) = 92 g
- ?Lv 41 decade ago
Ammonia's chemical formula is NH3. Determine the number of moles of each substance, then use the formula to determine the limiting factor, then calculate moles of ammonia formed, then convert to grams via its molar mass.
Hydrogen is 1.008g/mol. 100g H * mol/1.008g = 99.20634921 mol H
1 mole of gas at STP is 22.4 L. 60L N * mol/22.4L = 2.67857 mol N
Nitrogen is(by far) the limiting reagent.
Using the formula above, note that 2.67857 mol N will combine with 3 * 2.67857 mol H, giving:
2.67857 mol N
8.03571 mol H
Multiply by molar mass to obtain total mass:
2.67857 mol N * 14.007g/mol + 8.03571 mol H * 1.008g/mol = 37.51873g N + 8.1000g H for a total mass of 45.61872567g
Given that you only listed ONE(!) significant figure(if you omitted decimal places then you will have to re-examine them to determine sig figs in the answer) you MUST round this value to 50g NH3
